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115133201 = 831387147
BaseRepresentation
bin1101101110011…
…00101100010001
322000122101001122
412313030230101
5213433230301
615231412025
72565421211
oct667145421
9260571048
10115133201
1159a98307
1232684015
131ab11971
1411410241
15a19381b
hex6dccb11

115133201 has 4 divisors (see below), whose sum is σ = 116520432. Its totient is φ = 113745972.

The previous prime is 115133189. The next prime is 115133203. The reversal of 115133201 is 102331511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115133201 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 115133201.

It is not an unprimeable number, because it can be changed into a prime (115133203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 693491 + ... + 693656.

It is an arithmetic number, because the mean of its divisors is an integer number (29130108).

Almost surely, 2115133201 is an apocalyptic number.

It is an amenable number.

115133201 is a deficient number, since it is larger than the sum of its proper divisors (1387231).

115133201 is an equidigital number, since it uses as much as digits as its factorization.

115133201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1387230.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 115133201 is about 10730.0140260859. The cubic root of 115133201 is about 486.4820940059.

Adding to 115133201 its reverse (102331511), we get a palindrome (217464712).

The spelling of 115133201 in words is "one hundred fifteen million, one hundred thirty-three thousand, two hundred one".

Divisors: 1 83 1387147 115133201