1151340123035 has 4 divisors (see below), whose sum is σ = 1381608147648. Its totient is φ = 921072098424.

The previous prime is 1151340122993. The next prime is 1151340123049. The reversal of 1151340123035 is 5303210431511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1151340123035 - 2¹² = 1151340118939 is a prime.

It is a super-2 number, since 2×1151340123035² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1151340122989 and 1151340123007.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115134012299 + ... + 115134012308.

It is an arithmetic number, because the mean of its divisors is an integer number (345402036912).

Almost surely, 2^{1151340123035} is an apocalyptic number.

1151340123035 is a deficient number, since it is larger than the sum of its proper divisors (230268024613).

1151340123035 is an equidigital number, since it uses as much as digits as its factorization.

1151340123035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 230268024612.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 1151340123035 its reverse (5303210431511), we get a palindrome (6454550554546).

The spelling of 1151340123035 in words is "one trillion, one hundred fifty-one billion, three hundred forty million, one hundred twenty-three thousand, thirty-five".