Base | Representation |
---|---|
bin | 10101011100100100… |
… | …11101111100001001 |
3 | 1002201102122101022201 |
4 | 22232102131330021 |
5 | 142040041331101 |
6 | 5142305120201 |
7 | 555220324234 |
oct | 125622357411 |
9 | 32642571281 |
10 | 11514011401 |
11 | 49793a5202 |
12 | 2294029061 |
13 | 11165770c9 |
14 | 7b327241b |
15 | 475c73e01 |
hex | 2ae49df09 |
11514011401 has 4 divisors (see below), whose sum is σ = 11781779152. Its totient is φ = 11246243652.
The previous prime is 11514011371. The next prime is 11514011461. The reversal of 11514011401 is 10411041511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11514011401 - 29 = 11514010889 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11514011461) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133883811 + ... + 133883896.
It is an arithmetic number, because the mean of its divisors is an integer number (2945444788).
Almost surely, 211514011401 is an apocalyptic number.
It is an amenable number.
11514011401 is a deficient number, since it is larger than the sum of its proper divisors (267767751).
11514011401 is an equidigital number, since it uses as much as digits as its factorization.
11514011401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 267767750.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 11514011401 its reverse (10411041511), we get a palindrome (21925052912).
The spelling of 11514011401 in words is "eleven billion, five hundred fourteen million, eleven thousand, four hundred one".
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