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11514020241 = 328113658387
BaseRepresentation
bin10101011100100101…
…00000000110010001
31002201102122211110010
422232102200012101
5142040042121431
65142305225133
7555220362063
oct125622400621
932642584403
1011514020241
114979400909
1222940321a9
13111657b139
147b3275733
15475c76846
hex2ae4a0191

11514020241 has 8 divisors (see below), whose sum is σ = 15406661664. Its totient is φ = 7648696160.

The previous prime is 11514020237. The next prime is 11514020293. The reversal of 11514020241 is 14202041511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11514020241 - 22 = 11514020237 is a prime.

It is a super-2 number, since 2×115140202412 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11514020641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6828351 + ... + 6830036.

It is an arithmetic number, because the mean of its divisors is an integer number (1925832708).

Almost surely, 211514020241 is an apocalyptic number.

It is an amenable number.

11514020241 is a deficient number, since it is larger than the sum of its proper divisors (3892641423).

11514020241 is a wasteful number, since it uses less digits than its factorization.

11514020241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13658671.

The product of its (nonzero) digits is 320, while the sum is 21.

Adding to 11514020241 its reverse (14202041511), we get a palindrome (25716061752).

The spelling of 11514020241 in words is "eleven billion, five hundred fourteen million, twenty thousand, two hundred forty-one".

Divisors: 1 3 281 843 13658387 40975161 3838006747 11514020241