1151403143433 has 8 divisors (see below), whose sum is σ = 1536240796896. Its totient is φ = 767083792800.

The previous prime is 1151403143389. The next prime is 1151403143461. The reversal of 1151403143433 is 3343413041511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1151403143433 - 2¹⁸ = 1151402881289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1151403143394 and 1151403143403.

It is not an unprimeable number, because it can be changed into a prime (1151403143483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 129570523 + ... + 129579408.

It is an arithmetic number, because the mean of its divisors is an integer number (192030099612).

Almost surely, 2^{1151403143433} is an apocalyptic number.

It is an amenable number.

1151403143433 is a deficient number, since it is larger than the sum of its proper divisors (384837653463).

1151403143433 is a wasteful number, since it uses less digits than its factorization.

1151403143433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 259151415.

The product of its (nonzero) digits is 25920, while the sum is 33.

Adding to 1151403143433 its reverse (3343413041511), we get a palindrome (4494816184944).

The spelling of 1151403143433 in words is "one trillion, one hundred fifty-one billion, four hundred three million, one hundred forty-three thousand, four hundred thirty-three".