Base | Representation |
---|---|
bin | 10101011100101000… |
… | …10110001101110011 |
3 | 1002201110120102010000 |
4 | 22232110112031303 |
5 | 142040203112201 |
6 | 5142323441043 |
7 | 555224445441 |
oct | 125624261563 |
9 | 32643512100 |
10 | 11514504051 |
11 | 4979701356 |
12 | 2294226183 |
13 | 11166ba40b |
14 | 7b335db91 |
15 | 475d1ed86 |
hex | 2ae516373 |
11514504051 has 20 divisors (see below), whose sum is σ = 18105980200. Its totient is φ = 7272317376.
The previous prime is 11514504047. The next prime is 11514504059. The reversal of 11514504051 is 15040541511.
11514504051 is a `hidden beast` number, since 1 + 151 + 4 + 504 + 0 + 5 + 1 = 666.
It is not a de Polignac number, because 11514504051 - 22 = 11514504047 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11514504059) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 3739366 + ... + 3742443.
It is an arithmetic number, because the mean of its divisors is an integer number (905299010).
Almost surely, 211514504051 is an apocalyptic number.
11514504051 is a deficient number, since it is larger than the sum of its proper divisors (6591476149).
11514504051 is an equidigital number, since it uses as much as digits as its factorization.
11514504051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7481840 (or 7481831 counting only the distinct ones).
The product of its (nonzero) digits is 2000, while the sum is 27.
The spelling of 11514504051 in words is "eleven billion, five hundred fourteen million, five hundred four thousand, fifty-one".
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