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11514655500433 = 231493359981179
BaseRepresentation
bin1010011110001111011011…
…1100110110100010010001
31111202210100010202221200021
42213203312330312202101
53002124003302003213
640253432033023441
72265622616564341
oct247436674664221
944683303687607
1011514655500433
11373a379930838
12135b74a9b4b81
13656a9a90c477
142bb452d44d21
1514e7c8c52d8d
hexa78f6f36891

11514655500433 has 8 divisors (see below), whose sum is σ = 12095932248000. Its totient is φ = 10940098715568.

The previous prime is 11514655500431. The next prime is 11514655500457. The reversal of 11514655500433 is 33400555641511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11514655500433 - 21 = 11514655500431 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11514655500433.

It is not an unprimeable number, because it can be changed into a prime (11514655500431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1679987163 + ... + 1679994016.

It is an arithmetic number, because the mean of its divisors is an integer number (1511991531000).

Almost surely, 211514655500433 is an apocalyptic number.

It is an amenable number.

11514655500433 is a deficient number, since it is larger than the sum of its proper divisors (581276747567).

11514655500433 is a wasteful number, since it uses less digits than its factorization.

11514655500433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3359981351.

The product of its (nonzero) digits is 540000, while the sum is 43.

The spelling of 11514655500433 in words is "eleven trillion, five hundred fourteen billion, six hundred fifty-five million, five hundred thousand, four hundred thirty-three".

Divisors: 1 23 149 3427 3359981179 77279567117 500637195671 11514655500433