115152413125433 has 4 divisors (see below), whose sum is σ = 115152485506128. Its totient is φ = 115152340744740.

The previous prime is 115152413125417. The next prime is 115152413125439. The reversal of 115152413125433 is 334521314251511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115152413125433 - 2⁴ = 115152413125417 is a prime.

It is a super-2 number, since 2×115152413125433² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115152413125439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33749063 + ... + 37004108.

It is an arithmetic number, because the mean of its divisors is an integer number (28788121376532).

Almost surely, 2^{115152413125433} is an apocalyptic number.

It is an amenable number.

115152413125433 is a deficient number, since it is larger than the sum of its proper divisors (72380695).

115152413125433 is an equidigital number, since it uses as much as digits as its factorization.

115152413125433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72380694.

The product of its digits is 216000, while the sum is 41.

Adding to 115152413125433 its reverse (334521314251511), we get a palindrome (449673727376944).

The spelling of 115152413125433 in words is "one hundred fifteen trillion, one hundred fifty-two billion, four hundred thirteen million, one hundred twenty-five thousand, four hundred thirty-three".