Base | Representation |
---|---|
bin | 11010001011101101110101… |
… | …010000110101011001001011 |
3 | 120002201122110122011200012220 |
4 | 122023231311100311121023 |
5 | 110043142034343122311 |
6 | 1044525101010105123 |
7 | 33153424532536152 |
oct | 3213556520653113 |
9 | 502648418150186 |
10 | 115154335520331 |
11 | 33767752374458 |
12 | 10ab9821b7b1a3 |
13 | 4c34012bbcc03 |
14 | 20616dcbaa599 |
15 | d4a666462206 |
hex | 68bb7543564b |
115154335520331 has 16 divisors (see below), whose sum is σ = 154064103726624. Its totient is φ = 76507065448704.
The previous prime is 115154335520321. The next prime is 115154335520333. The reversal of 115154335520331 is 133025533451511.
It is not a de Polignac number, because 115154335520331 - 217 = 115154335389259 is a prime.
It is a super-2 number, since 2×1151543355203312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (115154335520333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 190332855 + ... + 190936911.
It is an arithmetic number, because the mean of its divisors is an integer number (9629006482914).
Almost surely, 2115154335520331 is an apocalyptic number.
115154335520331 is a deficient number, since it is larger than the sum of its proper divisors (38909768206293).
115154335520331 is a wasteful number, since it uses less digits than its factorization.
115154335520331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 821230.
The product of its (nonzero) digits is 405000, while the sum is 42.
Adding to 115154335520331 its reverse (133025533451511), we get a palindrome (248179868971842).
The spelling of 115154335520331 in words is "one hundred fifteen trillion, one hundred fifty-four billion, three hundred thirty-five million, five hundred twenty thousand, three hundred thirty-one".
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