Base | Representation |
---|---|
bin | 1010011110010101000001… |
… | …1001101001001010001011 |
3 | 1111202221012201122101222001 |
4 | 2213211100121221022023 |
5 | 3002140041443020133 |
6 | 40254241002411431 |
7 | 2266005041520226 |
oct | 247452031511213 |
9 | 44687181571861 |
10 | 11516156220043 |
11 | 373aa79a62682 |
12 | 135baa9500b77 |
13 | 656c797c4137 |
14 | 2bb5563945bd |
15 | 14e86589087d |
hex | a795066928b |
11516156220043 has 4 divisors (see below), whose sum is σ = 11654905090248. Its totient is φ = 11377407349840.
The previous prime is 11516156220001. The next prime is 11516156220067. The reversal of 11516156220043 is 34002265161511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11516156220043 - 29 = 11516156219531 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11516156219984 and 11516156220011.
It is not an unprimeable number, because it can be changed into a prime (11516156220083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69374434978 + ... + 69374435143.
It is an arithmetic number, because the mean of its divisors is an integer number (2913726272562).
Almost surely, 211516156220043 is an apocalyptic number.
11516156220043 is a deficient number, since it is larger than the sum of its proper divisors (138748870205).
11516156220043 is an equidigital number, since it uses as much as digits as its factorization.
11516156220043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 138748870204.
The product of its (nonzero) digits is 43200, while the sum is 37.
The spelling of 11516156220043 in words is "eleven trillion, five hundred sixteen billion, one hundred fifty-six million, two hundred twenty thousand, forty-three".
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