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11520214353 = 326120983997
BaseRepresentation
bin10101011101010100…
…01000010101010001
31002201212022112011200
422232222020111101
5142043133324403
65143050101413
7555324130524
oct125652102521
932655275150
1011520214353
11498195160a
12229611a869
1311179395ab
147b4008bbb
1547659bca3
hex2aea88551

11520214353 has 12 divisors (see below), whose sum is σ = 16913102388. Its totient is φ = 7554238560.

The previous prime is 11520214351. The next prime is 11520214367. The reversal of 11520214353 is 35341202511.

It can be written as a sum of positive squares in 2 ways, for example, as 4270883904 + 7249330449 = 65352^2 + 85143^2 .

It is not a de Polignac number, because 11520214353 - 21 = 11520214351 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11520214351) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10491450 + ... + 10492547.

It is an arithmetic number, because the mean of its divisors is an integer number (1409425199).

Almost surely, 211520214353 is an apocalyptic number.

It is an amenable number.

11520214353 is a deficient number, since it is larger than the sum of its proper divisors (5392888035).

11520214353 is a wasteful number, since it uses less digits than its factorization.

11520214353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20984064 (or 20984061 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 27.

Adding to 11520214353 its reverse (35341202511), we get a palindrome (46861416864).

The spelling of 11520214353 in words is "eleven billion, five hundred twenty million, two hundred fourteen thousand, three hundred fifty-three".

Divisors: 1 3 9 61 183 549 20983997 62951991 188855973 1280023817 3840071451 11520214353