Base | Representation |
---|---|
bin | 11010001100100001111101… |
… | …110010011100100100100011 |
3 | 120002220222221210220120201002 |
4 | 122030201331302130210203 |
5 | 110100101210124433011 |
6 | 1045010515344302215 |
7 | 33160445650401221 |
oct | 3214417562344443 |
9 | 502828853816632 |
10 | 115210313124131 |
11 | 33789468260735 |
12 | 10b0864491196b |
13 | 4c393941b66b4 |
14 | 20642cd359b11 |
15 | d4bd409b8c3b |
hex | 68c87dc9c923 |
115210313124131 has 8 divisors (see below), whose sum is σ = 115397561336784. Its totient is φ = 115023112565760.
The previous prime is 115210313124107. The next prime is 115210313124133. The reversal of 115210313124131 is 131421313012511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115210313124131 is a prime.
It is a super-2 number, since 2×1152103131241312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 115210313124094 and 115210313124103.
It is not an unprimeable number, because it can be changed into a prime (115210313124133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7072790 + ... + 16746491.
It is an arithmetic number, because the mean of its divisors is an integer number (14424695167098).
Almost surely, 2115210313124131 is an apocalyptic number.
115210313124131 is a deficient number, since it is larger than the sum of its proper divisors (187248212653).
115210313124131 is an equidigital number, since it uses as much as digits as its factorization.
115210313124131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23827141.
The product of its (nonzero) digits is 2160, while the sum is 29.
Adding to 115210313124131 its reverse (131421313012511), we get a palindrome (246631626136642).
The spelling of 115210313124131 in words is "one hundred fifteen trillion, two hundred ten billion, three hundred thirteen million, one hundred twenty-four thousand, one hundred thirty-one".
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