115230344034353 has 4 divisors (see below), whose sum is σ = 115231730747508. Its totient is φ = 115228957321200.

The previous prime is 115230344034347. The next prime is 115230344034389. The reversal of 115230344034353 is 353430443032511.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 84335055961744 + 30895288072609 = 9183412^2 + 5558353^2 .

It is a cyclic number.

It is not a de Polignac number, because 115230344034353 - 2²⁰ = 115230342985777 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 115230344034353.

It is not an unprimeable number, because it can be changed into a prime (115230344030353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 693231926 + ... + 693398127.

It is an arithmetic number, because the mean of its divisors is an integer number (28807932686877).

Almost surely, 2^{115230344034353} is an apocalyptic number.

It is an amenable number.

115230344034353 is a deficient number, since it is larger than the sum of its proper divisors (1386713155).

115230344034353 is an equidigital number, since it uses as much as digits as its factorization.

115230344034353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1386713154.

The product of its (nonzero) digits is 777600, while the sum is 41.

Adding to 115230344034353 its reverse (353430443032511), we get a palindrome (468660787066864).

The spelling of 115230344034353 in words is "one hundred fifteen trillion, two hundred thirty billion, three hundred forty-four million, thirty-four thousand, three hundred fifty-three".