11523644100433 has 4 divisors (see below), whose sum is σ = 11523774551220. Its totient is φ = 11523513649648.

The previous prime is 11523644100383. The next prime is 11523644100439. The reversal of 11523644100433 is 33400144632511.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2860911764929 + 8662732335504 = 1691423^2 + 2943252^2 .

It is a cyclic number.

It is not a de Polignac number, because 11523644100433 - 2¹³ = 11523644092241 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11523644100392 and 11523644100401.

It is not an unprimeable number, because it can be changed into a prime (11523644100439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65092798 + ... + 65269591.

It is an arithmetic number, because the mean of its divisors is an integer number (2880943637805).

Almost surely, 2^{11523644100433} is an apocalyptic number.

It is an amenable number.

11523644100433 is a deficient number, since it is larger than the sum of its proper divisors (130450787).

11523644100433 is an equidigital number, since it uses as much as digits as its factorization.

11523644100433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130450786.

The product of its (nonzero) digits is 103680, while the sum is 37.

Adding to 11523644100433 its reverse (33400144632511), we get a palindrome (44923788732944).

The spelling of 11523644100433 in words is "eleven trillion, five hundred twenty-three billion, six hundred forty-four million, one hundred thousand, four hundred thirty-three".