1152540113 has 4 divisors (see below), whose sum is σ = 1161615360. Its totient is φ = 1143464868.

The previous prime is 1152540101. The next prime is 1152540139. The reversal of 1152540113 is 3110452511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1152540113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1152540163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4537433 + ... + 4537686.

It is an arithmetic number, because the mean of its divisors is an integer number (290403840).

Almost surely, 2^1152540113 is an apocalyptic number.

It is an amenable number.

1152540113 is a deficient number, since it is larger than the sum of its proper divisors (9075247).

1152540113 is an equidigital number, since it uses as much as digits as its factorization.

1152540113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9075246.

The product of its (nonzero) digits is 600, while the sum is 23.

The square root of 1152540113 is about 33949.0811804974. The cubic root of 1152540113 is about 1048.4603626994.

Adding to 1152540113 its reverse (3110452511), we get a palindrome (4262992624).

The spelling of 1152540113 in words is "one billion, one hundred fifty-two million, five hundred forty thousand, one hundred thirteen".