Base | Representation |
---|---|
bin | 11010001101110110101010… |
… | …010110101110000000011011 |
3 | 120010020200200201100211101212 |
4 | 122031312222112232000123 |
5 | 110103043432304042301 |
6 | 1045120355415333335 |
7 | 33200145405661616 |
oct | 3215665226560033 |
9 | 503220621324355 |
10 | 115301255143451 |
11 | 33813a956a3893 |
12 | 10b221a508124b |
13 | 4c44b28225050 |
14 | 20688793d117d |
15 | d4e3b48c24bb |
hex | 68ddaa5ae01b |
115301255143451 has 4 divisors (see below), whose sum is σ = 124170582462192. Its totient is φ = 106431927824712.
The previous prime is 115301255143429. The next prime is 115301255143469. The reversal of 115301255143451 is 154341552103511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 115301255143451 - 26 = 115301255143387 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 115301255143399 and 115301255143408.
It is not an unprimeable number, because it can be changed into a prime (115301255143351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4434663659351 + ... + 4434663659376.
It is an arithmetic number, because the mean of its divisors is an integer number (31042645615548).
Almost surely, 2115301255143451 is an apocalyptic number.
115301255143451 is a deficient number, since it is larger than the sum of its proper divisors (8869327318741).
115301255143451 is an equidigital number, since it uses as much as digits as its factorization.
115301255143451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8869327318740.
The product of its (nonzero) digits is 180000, while the sum is 41.
The spelling of 115301255143451 in words is "one hundred fifteen trillion, three hundred one billion, two hundred fifty-five million, one hundred forty-three thousand, four hundred fifty-one".
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