Base | Representation |
---|---|
bin | 110101101100100001… |
… | …0010001001000000001 |
3 | 102000122011212020200121 |
4 | 1223121002101020001 |
5 | 3342123430300001 |
6 | 124550050020241 |
7 | 11221333141126 |
oct | 1533102211001 |
9 | 360564766617 |
10 | 115310400001 |
11 | 449a2795245 |
12 | 1a421277681 |
13 | ab48758224 |
14 | 581c5a474d |
15 | 2eed4146a1 |
hex | 1ad9091201 |
115310400001 has 4 divisors (see below), whose sum is σ = 115735899904. Its totient is φ = 114884900100.
The previous prime is 115310399969. The next prime is 115310400031. The reversal of 115310400001 is 100004013511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 115310400001 - 25 = 115310399969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (115310400031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 212749545 + ... + 212750086.
It is an arithmetic number, because the mean of its divisors is an integer number (28933974976).
Almost surely, 2115310400001 is an apocalyptic number.
It is an amenable number.
115310400001 is a deficient number, since it is larger than the sum of its proper divisors (425499903).
115310400001 is an equidigital number, since it uses as much as digits as its factorization.
115310400001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 425499902.
The product of its (nonzero) digits is 60, while the sum is 16.
Adding to 115310400001 its reverse (100004013511), we get a palindrome (215314413512).
The spelling of 115310400001 in words is "one hundred fifteen billion, three hundred ten million, four hundred thousand, one".
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