Base | Representation |
---|---|
bin | 11010001110011100000110… |
… | …110100101110111101111011 |
3 | 120010101112110202012012111011 |
4 | 122032130012310232331323 |
5 | 110104223303033034433 |
6 | 1045151045155214351 |
7 | 33203100635002405 |
oct | 3216340664567573 |
9 | 503345422165434 |
10 | 115341461221243 |
11 | 3382a047a06154 |
12 | 10b29b45ba73b7 |
13 | 4c48864bac11a |
14 | 206a7b10c3b75 |
15 | d504695143cd |
hex | 68e706d2ef7b |
115341461221243 has 4 divisors (see below), whose sum is σ = 115459517989080. Its totient is φ = 115223404453408.
The previous prime is 115341461221237. The next prime is 115341461221247. The reversal of 115341461221243 is 342122164143511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 115341461221243 - 217 = 115341461090171 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 115341461221196 and 115341461221205.
It is not an unprimeable number, because it can be changed into a prime (115341461221247) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59028382453 + ... + 59028384406.
It is an arithmetic number, because the mean of its divisors is an integer number (28864879497270).
Almost surely, 2115341461221243 is an apocalyptic number.
115341461221243 is a deficient number, since it is larger than the sum of its proper divisors (118056767837).
115341461221243 is an equidigital number, since it uses as much as digits as its factorization.
115341461221243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 118056767836.
The product of its digits is 138240, while the sum is 40.
The spelling of 115341461221243 in words is "one hundred fifteen trillion, three hundred forty-one billion, four hundred sixty-one million, two hundred twenty-one thousand, two hundred forty-three".
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