11540113 has 4 divisors (see below), whose sum is σ = 12427828. Its totient is φ = 10652400.

The previous prime is 11540107. The next prime is 11540129. The reversal of 11540113 is 31104511.

11540113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6190144 + 5349969 = 2488^2 + 2313^2 .

It is a cyclic number.

It is not a de Polignac number, because 11540113 - 2¹³ = 11531921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11540143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 443838 + ... + 443863.

It is an arithmetic number, because the mean of its divisors is an integer number (3106957).

Almost surely, 2^11540113 is an apocalyptic number.

11540113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11540113 is a deficient number, since it is larger than the sum of its proper divisors (887715).

11540113 is an equidigital number, since it uses as much as digits as its factorization.

11540113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 887714.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 11540113 is about 3397.0741822928. The cubic root of 11540113 is about 225.9800084125.

Adding to 11540113 its reverse (31104511), we get a palindrome (42644624).

The spelling of 11540113 in words is "eleven million, five hundred forty thousand, one hundred thirteen".