1154027442131 has 4 divisors (see below), whose sum is σ = 1163114272512. Its totient is φ = 1144940611752.

The previous prime is 1154027442109. The next prime is 1154027442157. The reversal of 1154027442131 is 1312447204511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1154027442131 - 2⁶ = 1154027442067 is a prime.

It is a super-2 number, since 2×1154027442131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1154027442091 and 1154027442100.

It is not an unprimeable number, because it can be changed into a prime (1154027492131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4543415000 + ... + 4543415253.

It is an arithmetic number, because the mean of its divisors is an integer number (290778568128).

Almost surely, 2^{1154027442131} is an apocalyptic number.

1154027442131 is a deficient number, since it is larger than the sum of its proper divisors (9086830381).

1154027442131 is an equidigital number, since it uses as much as digits as its factorization.

1154027442131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9086830380.

The product of its (nonzero) digits is 26880, while the sum is 35.

The spelling of 1154027442131 in words is "one trillion, one hundred fifty-four billion, twenty-seven million, four hundred forty-two thousand, one hundred thirty-one".