115404403 has 4 divisors (see below), whose sum is σ = 115433920. Its totient is φ = 115374888.

The previous prime is 115404391. The next prime is 115404433. The reversal of 115404403 is 304404511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304404511 = 1327 ⋅229393.

It is a cyclic number.

It is not a de Polignac number, because 115404403 - 2¹⁷ = 115273331 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115404433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7800 + ... + 17077.

It is an arithmetic number, because the mean of its divisors is an integer number (28858480).

Almost surely, 2^115404403 is an apocalyptic number.

115404403 is a deficient number, since it is larger than the sum of its proper divisors (29517).

115404403 is an equidigital number, since it uses as much as digits as its factorization.

115404403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29516.

The product of its (nonzero) digits is 960, while the sum is 22.

The square root of 115404403 is about 10742.6441344764. The cubic root of 115404403 is about 486.8637720911.

Adding to 115404403 its reverse (304404511), we get a palindrome (419808914).

The spelling of 115404403 in words is "one hundred fifteen million, four hundred four thousand, four hundred three".