115405013532131 has 4 divisors (see below), whose sum is σ = 115406614828152. Its totient is φ = 115403412236112.

The previous prime is 115405013532097. The next prime is 115405013532139. The reversal of 115405013532131 is 131235310504511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115405013532131 is a prime.

It is a super-2 number, since 2×115405013532131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115405013532091 and 115405013532100.

It is not an unprimeable number, because it can be changed into a prime (115405013532139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 800539901 + ... + 800684046.

It is an arithmetic number, because the mean of its divisors is an integer number (28851653707038).

Almost surely, 2^{115405013532131} is an apocalyptic number.

115405013532131 is a deficient number, since it is larger than the sum of its proper divisors (1601296021).

115405013532131 is an equidigital number, since it uses as much as digits as its factorization.

115405013532131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1601296020.

The product of its (nonzero) digits is 27000, while the sum is 35.

The spelling of 115405013532131 in words is "one hundred fifteen trillion, four hundred five billion, thirteen million, five hundred thirty-two thousand, one hundred thirty-one".