11540634041 has 4 divisors (see below), whose sum is σ = 11541881232. Its totient is φ = 11539386852.

The previous prime is 11540634019. The next prime is 11540634043. The reversal of 11540634041 is 14043604511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14043604511 = 17 ⋅826094383.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11540634041 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11540633995 and 11540634013.

It is not an unprimeable number, because it can be changed into a prime (11540634043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 609611 + ... + 628256.

It is an arithmetic number, because the mean of its divisors is an integer number (2885470308).

Almost surely, 2^11540634041 is an apocalyptic number.

It is an amenable number.

11540634041 is a deficient number, since it is larger than the sum of its proper divisors (1247191).

11540634041 is an equidigital number, since it uses as much as digits as its factorization.

11540634041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1247190.

The product of its (nonzero) digits is 5760, while the sum is 29.

The spelling of 11540634041 in words is "eleven billion, five hundred forty million, six hundred thirty-four thousand, forty-one".