1154135033 has 4 divisors (see below), whose sum is σ = 1170390528. Its totient is φ = 1137879540.

The previous prime is 1154135023. The next prime is 1154135057. The reversal of 1154135033 is 3305314511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3305314511 = 15121 ⋅218591.

It is a cyclic number.

It is not a de Polignac number, because 1154135033 - 2¹² = 1154130937 is a prime.

It is a super-2 number, since 2×1154135033² = 2664055348795822178, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1154134993 and 1154135011.

It is not an unprimeable number, because it can be changed into a prime (1154135023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8127641 + ... + 8127782.

It is an arithmetic number, because the mean of its divisors is an integer number (292597632).

Almost surely, 2^1154135033 is an apocalyptic number.

It is an amenable number.

1154135033 is a deficient number, since it is larger than the sum of its proper divisors (16255495).

1154135033 is an equidigital number, since it uses as much as digits as its factorization.

1154135033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16255494.

The product of its (nonzero) digits is 2700, while the sum is 26.

The square root of 1154135033 is about 33972.5629442349. The cubic root of 1154135033 is about 1048.9437702104.

Adding to 1154135033 its reverse (3305314511), we get a palindrome (4459449544).

The spelling of 1154135033 in words is "one billion, one hundred fifty-four million, one hundred thirty-five thousand, thirty-three".