11541378433 has 4 divisors (see below), whose sum is σ = 12429176788. Its totient is φ = 10653580080.

The previous prime is 11541378391. The next prime is 11541378463. The reversal of 11541378433 is 33487314511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33487314511 = 7 ⋅4783902073.

It can be written as a sum of positive squares in 2 ways, for example, as 4871062849 + 6670315584 = 69793^2 + 81672^2 .

It is a de Polignac number, because none of the positive numbers 2^k-11541378433 is a prime.

It is a super-2 number, since 2×11541378433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11541378463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 443899158 + ... + 443899183.

It is an arithmetic number, because the mean of its divisors is an integer number (3107294197).

Almost surely, 2^11541378433 is an apocalyptic number.

11541378433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11541378433 is a deficient number, since it is larger than the sum of its proper divisors (887798355).

11541378433 is an equidigital number, since it uses as much as digits as its factorization.

11541378433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 887798354.

The product of its digits is 120960, while the sum is 40.

The spelling of 11541378433 in words is "eleven billion, five hundred forty-one million, three hundred seventy-eight thousand, four hundred thirty-three".