115414403332441 has 4 divisors (see below), whose sum is σ = 115415255920384. Its totient is φ = 115413550744500.

The previous prime is 115414403332411. The next prime is 115414403332513. The reversal of 115414403332441 is 144233304414511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115414403332441 - 2³⁷ = 115276964378969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115414403332394 and 115414403332403.

It is not an unprimeable number, because it can be changed into a prime (115414403332411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 426090885 + ... + 426361666.

It is an arithmetic number, because the mean of its divisors is an integer number (28853813980096).

Almost surely, 2^{115414403332441} is an apocalyptic number.

It is an amenable number.

115414403332441 is a deficient number, since it is larger than the sum of its proper divisors (852587943).

115414403332441 is an equidigital number, since it uses as much as digits as its factorization.

115414403332441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 852587942.

The product of its (nonzero) digits is 276480, while the sum is 40.

Adding to 115414403332441 its reverse (144233304414511), we get a palindrome (259647707746952).

The spelling of 115414403332441 in words is "one hundred fifteen trillion, four hundred fourteen billion, four hundred three million, three hundred thirty-two thousand, four hundred forty-one".