115443433201 has 4 divisors (see below), whose sum is σ = 115444428400. Its totient is φ = 115442438004.

The previous prime is 115443433093. The next prime is 115443433207. The reversal of 115443433201 is 102334344511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 115443433201 - 2¹⁹ = 115442908913 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115443433207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 296511 + ... + 564628.

It is an arithmetic number, because the mean of its divisors is an integer number (28861107100).

Almost surely, 2^115443433201 is an apocalyptic number.

It is an amenable number.

115443433201 is a deficient number, since it is larger than the sum of its proper divisors (995199).

115443433201 is an equidigital number, since it uses as much as digits as its factorization.

115443433201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 995198.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 115443433201 its reverse (102334344511), we get a palindrome (217777777712).

The spelling of 115443433201 in words is "one hundred fifteen billion, four hundred forty-three million, four hundred thirty-three thousand, two hundred one".