Base | Representation |
---|---|
bin | 11010010000110011110111… |
… | …011101011011110010110011 |
3 | 120010222010002002020020022222 |
4 | 122100303313131123302303 |
5 | 110114411014011244103 |
6 | 1045353554444351255 |
7 | 33220630003402364 |
oct | 3220636735336263 |
9 | 503863062206288 |
10 | 115504412212403 |
11 | 33892167555685 |
12 | 10b55641b4552b |
13 | 4c5b033631056 |
14 | 207462c8c3b6b |
15 | d548050b4638 |
hex | 690cf775bcb3 |
115504412212403 has 4 divisors (see below), whose sum is σ = 115504434066840. Its totient is φ = 115504390357968.
The previous prime is 115504412212391. The next prime is 115504412212421. The reversal of 115504412212403 is 304212214405511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 115504412212403 - 216 = 115504412146867 is a prime.
It is a super-2 number, since 2×1155044122124032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (115504412212103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2501468 + ... + 15403446.
It is an arithmetic number, because the mean of its divisors is an integer number (28876108516710).
Almost surely, 2115504412212403 is an apocalyptic number.
115504412212403 is a deficient number, since it is larger than the sum of its proper divisors (21854437).
115504412212403 is an equidigital number, since it uses as much as digits as its factorization.
115504412212403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21854436.
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 115504412212403 its reverse (304212214405511), we get a palindrome (419716626617914).
The spelling of 115504412212403 in words is "one hundred fifteen trillion, five hundred four billion, four hundred twelve million, two hundred twelve thousand, four hundred three".
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