Base | Representation |
---|---|
bin | 1010100000011010101001… |
… | …0000111010111100011001 |
3 | 1111220100210101111011212120 |
4 | 2220012222100322330121 |
5 | 3003232021021341101 |
6 | 40322532033331453 |
7 | 2301414625431414 |
oct | 250065220727431 |
9 | 44810711434776 |
10 | 11552023621401 |
11 | 37542051a013a |
12 | 1366a39406b89 |
13 | 65a474639753 |
14 | 2bd199b72b7b |
15 | 15076465db36 |
hex | a81aa43af19 |
11552023621401 has 8 divisors (see below), whose sum is σ = 15899559393024. Its totient is φ = 7452918465360.
The previous prime is 11552023621387. The next prime is 11552023621441. The reversal of 11552023621401 is 10412632025511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11552023621401 - 210 = 11552023620377 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11552023621441) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62107653786 + ... + 62107653971.
It is an arithmetic number, because the mean of its divisors is an integer number (1987444924128).
Almost surely, 211552023621401 is an apocalyptic number.
It is an amenable number.
11552023621401 is a deficient number, since it is larger than the sum of its proper divisors (4347535771623).
11552023621401 is a wasteful number, since it uses less digits than its factorization.
11552023621401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 124215307791.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 11552023621401 its reverse (10412632025511), we get a palindrome (21964655646912).
The spelling of 11552023621401 in words is "eleven trillion, five hundred fifty-two billion, twenty-three million, six hundred twenty-one thousand, four hundred one".
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