Base | Representation |
---|---|
bin | 11010010001000010110011… |
… | …011001100011101001110001 |
3 | 120011000122110210120011020010 |
4 | 122101002303121203221301 |
5 | 110120141340223331023 |
6 | 1045405210122405133 |
7 | 33222035306230131 |
oct | 3221026331435161 |
9 | 504018423504203 |
10 | 115520450214513 |
11 | 33898a47596a83 |
12 | 10b587790607a9 |
13 | 4c5c6bb231626 |
14 | 2075310908ac1 |
15 | d54e430b5093 |
hex | 6910b3663a71 |
115520450214513 has 4 divisors (see below), whose sum is σ = 154027266952688. Its totient is φ = 77013633476340.
The previous prime is 115520450214497. The next prime is 115520450214517. The reversal of 115520450214513 is 315412054025511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 115520450214513 - 24 = 115520450214497 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (115520450214517) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19253408369083 + ... + 19253408369088.
It is an arithmetic number, because the mean of its divisors is an integer number (38506816738172).
Almost surely, 2115520450214513 is an apocalyptic number.
It is an amenable number.
115520450214513 is a deficient number, since it is larger than the sum of its proper divisors (38506816738175).
115520450214513 is an equidigital number, since it uses as much as digits as its factorization.
115520450214513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38506816738174.
The product of its (nonzero) digits is 120000, while the sum is 39.
The spelling of 115520450214513 in words is "one hundred fifteen trillion, five hundred twenty billion, four hundred fifty million, two hundred fourteen thousand, five hundred thirteen".
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