Search a number
-
+
11555231253169 = 67172466138107
BaseRepresentation
bin1010100000100110100101…
…1101000100001010110001
31111220200001221012202110011
42220021221131010022301
53003310103200100134
640324222220134521
72301560255025502
oct250115135041261
944820057182404
1011555231253169
11375560088638a
121367593697441
1365a86604ac06
142bd3c1b86ba9
151508a1068264
hexa82697442b1

11555231253169 has 4 divisors (see below), whose sum is σ = 11727697391344. Its totient is φ = 11382765114996.

The previous prime is 11555231253149. The next prime is 11555231253187. The reversal of 11555231253169 is 96135213255511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11555231253169 is a prime.

It is a super-2 number, since 2×115552312531692 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11555231253149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86233068987 + ... + 86233069120.

It is an arithmetic number, because the mean of its divisors is an integer number (2931924347836).

Almost surely, 211555231253169 is an apocalyptic number.

It is an amenable number.

11555231253169 is a deficient number, since it is larger than the sum of its proper divisors (172466138175).

11555231253169 is an equidigital number, since it uses as much as digits as its factorization.

11555231253169 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 172466138174.

The product of its digits is 1215000, while the sum is 49.

The spelling of 11555231253169 in words is "eleven trillion, five hundred fifty-five billion, two hundred thirty-one million, two hundred fifty-three thousand, one hundred sixty-nine".

Divisors: 1 67 172466138107 11555231253169