Base | Representation |
---|---|
bin | 110101110011101111… |
… | …0000000110110000011 |
3 | 102001021001111222000222 |
4 | 1223213132000312003 |
5 | 3343122423214441 |
6 | 125030100133255 |
7 | 11230333335422 |
oct | 1534736006603 |
9 | 361231458028 |
10 | 115552554371 |
11 | 4500744a421 |
12 | 1a48a39722b |
13 | ab86981837 |
14 | 58427db2b9 |
15 | 30147e8d4b |
hex | 1ae7780d83 |
115552554371 has 4 divisors (see below), whose sum is σ = 115609227600. Its totient is φ = 115495881144.
The previous prime is 115552554347. The next prime is 115552554413. The reversal of 115552554371 is 173455255511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 115552554371 - 26 = 115552554307 is a prime.
It is a super-2 number, since 2×1155525543712 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (115552550371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28333556 + ... + 28337633.
It is an arithmetic number, because the mean of its divisors is an integer number (28902306900).
Almost surely, 2115552554371 is an apocalyptic number.
115552554371 is a deficient number, since it is larger than the sum of its proper divisors (56673229).
115552554371 is an equidigital number, since it uses as much as digits as its factorization.
115552554371 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56673228.
The product of its digits is 525000, while the sum is 44.
The spelling of 115552554371 in words is "one hundred fifteen billion, five hundred fifty-two million, five hundred fifty-four thousand, three hundred seventy-one".
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