1155531403 has 4 divisors (see below), whose sum is σ = 1244418448. Its totient is φ = 1066644360.

The previous prime is 1155531401. The next prime is 1155531451. The reversal of 1155531403 is 3041355511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1155531403 - 2¹ = 1155531401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1155531401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44443503 + ... + 44443528.

It is an arithmetic number, because the mean of its divisors is an integer number (311104612).

Almost surely, 2^1155531403 is an apocalyptic number.

1155531403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1155531403 is a deficient number, since it is larger than the sum of its proper divisors (88887045).

1155531403 is an equidigital number, since it uses as much as digits as its factorization.

1155531403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 88887044.

The product of its (nonzero) digits is 4500, while the sum is 28.

The square root of 1155531403 is about 33993.1081691569. The cubic root of 1155531403 is about 1049.3666332943.

Adding to 1155531403 its reverse (3041355511), we get a palindrome (4196886914).

The spelling of 1155531403 in words is "one billion, one hundred fifty-five million, five hundred thirty-one thousand, four hundred three".