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11555555506161 = 33851851835387
BaseRepresentation
bin1010100000100111110011…
…0001111111011111110001
31111220200220112100111221020
42220021330301333133301
53003311234202144121
640324314322050053
72301601303106502
oct250117461773761
944820815314836
1011555555506161
113755757915467
1213676641a9929
1365a8b828aba4
142bd412c70ba9
151508be7681c6
hexa827cc7f7f1

11555555506161 has 4 divisors (see below), whose sum is σ = 15407407341552. Its totient is φ = 7703703670772.

The previous prime is 11555555506133. The next prime is 11555555506177. The reversal of 11555555506161 is 16160555555511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11555555506161 - 230 = 11554481764337 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11555555504161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1925925917691 + ... + 1925925917696.

It is an arithmetic number, because the mean of its divisors is an integer number (3851851835388).

Almost surely, 211555555506161 is an apocalyptic number.

It is an amenable number.

11555555506161 is a deficient number, since it is larger than the sum of its proper divisors (3851851835391).

11555555506161 is an equidigital number, since it uses as much as digits as its factorization.

11555555506161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3851851835390.

The product of its (nonzero) digits is 2812500, while the sum is 51.

The spelling of 11555555506161 in words is "eleven trillion, five hundred fifty-five billion, five hundred fifty-five million, five hundred six thousand, one hundred sixty-one".

Divisors: 1 3 3851851835387 11555555506161