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115556042314113 = 338518680771371
BaseRepresentation
bin11010010001100011111100…
…110110101001000110000001
3120011011001100021101011010020
4122101203330312221012001
5110121232233313022423
61045433414000524053
733224435311126302
oct3221437466510601
9504131307334106
10115556042314113
113390205138a225
1210b63650920629
134c62b71015bab
142076d299027a9
15d55d27b024e3
hex6918fcda9181

115556042314113 has 4 divisors (see below), whose sum is σ = 154074723085488. Its totient is φ = 77037361542740.

The previous prime is 115556042314087. The next prime is 115556042314117. The reversal of 115556042314113 is 311413240655511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115556042314113 - 236 = 115487322837377 is a prime.

It is not an unprimeable number, because it can be changed into a prime (115556042314117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19259340385683 + ... + 19259340385688.

It is an arithmetic number, because the mean of its divisors is an integer number (38518680771372).

Almost surely, 2115556042314113 is an apocalyptic number.

It is an amenable number.

115556042314113 is a deficient number, since it is larger than the sum of its proper divisors (38518680771375).

115556042314113 is an equidigital number, since it uses as much as digits as its factorization.

115556042314113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38518680771374.

The product of its (nonzero) digits is 216000, while the sum is 42.

Adding to 115556042314113 its reverse (311413240655511), we get a palindrome (426969282969624).

The spelling of 115556042314113 in words is "one hundred fifteen trillion, five hundred fifty-six billion, forty-two million, three hundred fourteen thousand, one hundred thirteen".

Divisors: 1 3 38518680771371 115556042314113