115642147 has 4 divisors (see below), whose sum is σ = 117226360. Its totient is φ = 114057936.

The previous prime is 115642141. The next prime is 115642171. The reversal of 115642147 is 741246511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115642147 - 2⁷ = 115642019 is a prime.

It is a super-3 number, since 3×115642147³ (a number of 25 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115642141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 791997 + ... + 792142.

It is an arithmetic number, because the mean of its divisors is an integer number (29306590).

Almost surely, 2^115642147 is an apocalyptic number.

115642147 is a deficient number, since it is larger than the sum of its proper divisors (1584213).

115642147 is an equidigital number, since it uses as much as digits as its factorization.

115642147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1584212.

The product of its digits is 6720, while the sum is 31.

The square root of 115642147 is about 10753.7038735498. The cubic root of 115642147 is about 487.1978712643.

Adding to 115642147 its reverse (741246511), we get a palindrome (856888658).

The spelling of 115642147 in words is "one hundred fifteen million, six hundred forty-two thousand, one hundred forty-seven".