Base | Representation |
---|---|
bin | 10000111000010001111… |
… | …001001110011101000001 |
3 | 11002220000022100120110001 |
4 | 100320101321032131001 |
5 | 123001024443242001 |
6 | 2244511505240001 |
7 | 146542300041061 |
oct | 20702171163501 |
9 | 4086008316401 |
10 | 1159941384001 |
11 | 407a23742a84 |
12 | 16897a033001 |
13 | 854c735142a |
14 | 401da25d3a1 |
15 | 2028cec6001 |
hex | 10e11e4e741 |
1159941384001 has 4 divisors (see below), whose sum is σ = 1210373618112. Its totient is φ = 1109509149892.
The previous prime is 1159941383983. The next prime is 1159941384067. The reversal of 1159941384001 is 1004831499511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1159941384001 - 219 = 1159940859713 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1159941382001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25216117021 + ... + 25216117066.
It is an arithmetic number, because the mean of its divisors is an integer number (302593404528).
Almost surely, 21159941384001 is an apocalyptic number.
It is an amenable number.
1159941384001 is a deficient number, since it is larger than the sum of its proper divisors (50432234111).
1159941384001 is an equidigital number, since it uses as much as digits as its factorization.
1159941384001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50432234110.
The product of its (nonzero) digits is 155520, while the sum is 46.
The spelling of 1159941384001 in words is "one trillion, one hundred fifty-nine billion, nine hundred forty-one million, three hundred eighty-four thousand, one".
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