1160315113 has 4 divisors (see below), whose sum is σ = 1162252800. Its totient is φ = 1158377428.

The previous prime is 1160315087. The next prime is 1160315119. The reversal of 1160315113 is 3115130611.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1160315113 - 2⁵ = 1160315081 is a prime.

It is a super-2 number, since 2×1160315113² = 2692662322912405538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1160315119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 967945 + ... + 969142.

It is an arithmetic number, because the mean of its divisors is an integer number (290563200).

Almost surely, 2^1160315113 is an apocalyptic number.

It is an amenable number.

1160315113 is a deficient number, since it is larger than the sum of its proper divisors (1937687).

1160315113 is an equidigital number, since it uses as much as digits as its factorization.

1160315113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1937686.

The product of its (nonzero) digits is 270, while the sum is 22.

The square root of 1160315113 is about 34063.3984358578. The cubic root of 1160315113 is about 1050.8127080592.

Adding to 1160315113 its reverse (3115130611), we get a palindrome (4275445724).

The spelling of 1160315113 in words is "one billion, one hundred sixty million, three hundred fifteen thousand, one hundred thirteen".