Base | Representation |
---|---|
bin | 10101100111010110… |
… | …00110010011000001 |
3 | 1002221201122021101211 |
4 | 22303223012103001 |
5 | 142231203313431 |
6 | 5155253330121 |
7 | 560365245364 |
oct | 126353062301 |
9 | 32851567354 |
10 | 11604354241 |
11 | 4a153a0107 |
12 | 22ba336941 |
13 | 112c1b90cc |
14 | 7c126c0db |
15 | 47db6c2b1 |
hex | 2b3ac64c1 |
11604354241 has 4 divisors (see below), whose sum is σ = 12286963332. Its totient is φ = 10921745152.
The previous prime is 11604354233. The next prime is 11604354247. The reversal of 11604354241 is 14245340611.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7523827600 + 4080526641 = 86740^2 + 63879^2 .
It is a cyclic number.
It is not a de Polignac number, because 11604354241 - 23 = 11604354233 is a prime.
It is a super-2 number, since 2×116043542412 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11604354247) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 341304520 + ... + 341304553.
It is an arithmetic number, because the mean of its divisors is an integer number (3071740833).
Almost surely, 211604354241 is an apocalyptic number.
It is an amenable number.
11604354241 is a deficient number, since it is larger than the sum of its proper divisors (682609091).
11604354241 is an equidigital number, since it uses as much as digits as its factorization.
11604354241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 682609090.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 11604354241 its reverse (14245340611), we get a palindrome (25849694852).
The spelling of 11604354241 in words is "eleven billion, six hundred four million, three hundred fifty-four thousand, two hundred forty-one".
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