116132342041403 has 4 divisors (see below), whose sum is σ = 116132533100448. Its totient is φ = 116132150982360.

The previous prime is 116132342041399. The next prime is 116132342041421. The reversal of 116132342041403 is 304140243231611.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 116132342041403 - 2² = 116132342041399 is a prime.

It is a super-3 number, since 3×116132342041403³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (116132342041423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94614851 + ... + 95834412.

It is an arithmetic number, because the mean of its divisors is an integer number (29033133275112).

Almost surely, 2^{116132342041403} is an apocalyptic number.

116132342041403 is a deficient number, since it is larger than the sum of its proper divisors (191059045).

116132342041403 is an equidigital number, since it uses as much as digits as its factorization.

116132342041403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191059044.

The product of its (nonzero) digits is 41472, while the sum is 35.

The spelling of 116132342041403 in words is "one hundred sixteen trillion, one hundred thirty-two billion, three hundred forty-two million, forty-one thousand, four hundred three".