116264537 has 4 divisors (see below), whose sum is σ = 117736320. Its totient is φ = 114792756.

The previous prime is 116264531. The next prime is 116264543. The reversal of 116264537 is 735462611.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 735462611 = 13 ⋅56574047.

It is an interprime number because it is at equal distance from previous prime (116264531) and next prime (116264543).

It is a cyclic number.

It is not a de Polignac number, because 116264537 - 2¹⁰ = 116263513 is a prime.

It is a super-3 number, since 3×116264537³ (a number of 25 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 116264497 and 116264506.

It is not an unprimeable number, because it can be changed into a prime (116264531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 735773 + ... + 735930.

It is an arithmetic number, because the mean of its divisors is an integer number (29434080).

Almost surely, 2^116264537 is an apocalyptic number.

It is an amenable number.

116264537 is a deficient number, since it is larger than the sum of its proper divisors (1471783).

116264537 is an equidigital number, since it uses as much as digits as its factorization.

116264537 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1471782.

The product of its digits is 30240, while the sum is 35.

The square root of 116264537 is about 10782.6034425829. The cubic root of 116264537 is about 488.0703464499.

The spelling of 116264537 in words is "one hundred sixteen million, two hundred sixty-four thousand, five hundred thirty-seven".