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11650728540803 = 111059157140073
BaseRepresentation
bin1010100110001010010110…
…0010010011101010000011
31112020210120022012121112012
42221202211202103222003
53011341143001301203
640440134254323135
72311510625415632
oct251424542235203
945223508177465
1011650728540803
113792056588aa0
121381ba54b94ab
13666874a443c1
142c3c80bd3519
151530ded2abd8
hexa98a5893a83

11650728540803 has 4 divisors (see below), whose sum is σ = 12709885680888. Its totient is φ = 10591571400720.

The previous prime is 11650728540767. The next prime is 11650728540827. The reversal of 11650728540803 is 30804582705611.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11650728540803 - 220 = 11650727492227 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11650728560803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 529578570026 + ... + 529578570047.

It is an arithmetic number, because the mean of its divisors is an integer number (3177471420222).

Almost surely, 211650728540803 is an apocalyptic number.

11650728540803 is a deficient number, since it is larger than the sum of its proper divisors (1059157140085).

11650728540803 is a wasteful number, since it uses less digits than its factorization.

11650728540803 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1059157140084.

The product of its (nonzero) digits is 1612800, while the sum is 50.

The spelling of 11650728540803 in words is "eleven trillion, six hundred fifty billion, seven hundred twenty-eight million, five hundred forty thousand, eight hundred three".

Divisors: 1 11 1059157140073 11650728540803