11664214003 has 16 divisors (see below), whose sum is σ = 12775217056. Its totient is φ = 10583965440.

The previous prime is 11664213973. The next prime is 11664214027. The reversal of 11664214003 is 30041246611.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11664214003 is a prime.

It is a super-3 number, since 3×11664214003³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11664214603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1691200 + ... + 1698082.

It is an arithmetic number, because the mean of its divisors is an integer number (798451066).

Almost surely, 2^11664214003 is an apocalyptic number.

11664214003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11664214003 is a deficient number, since it is larger than the sum of its proper divisors (1111003053).

11664214003 is a wasteful number, since it uses less digits than its factorization.

11664214003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9094.

The product of its (nonzero) digits is 3456, while the sum is 28.

The spelling of 11664214003 in words is "eleven billion, six hundred sixty-four million, two hundred fourteen thousand, three".