Base | Representation |
---|---|
bin | 11010100010011000100111… |
… | …010010011110001110001011 |
3 | 120022020120022221201112212121 |
4 | 122202120213102132032023 |
5 | 110244202340204032212 |
6 | 1052120444310552111 |
7 | 33404112436160650 |
oct | 3242304722361613 |
9 | 508216287645777 |
10 | 116712100455307 |
11 | 34208362035425 |
12 | 1110b706368637 |
13 | 5017b999a57c6 |
14 | 20b6c78121c27 |
15 | d75e39c17d07 |
hex | 6a262749e38b |
116712100455307 has 4 divisors (see below), whose sum is σ = 133385257663216. Its totient is φ = 100038943247400.
The previous prime is 116712100455257. The next prime is 116712100455371. The reversal of 116712100455307 is 703554001217611.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 116712100455307 - 219 = 116712099931019 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (116712100455407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8336578603944 + ... + 8336578603957.
It is an arithmetic number, because the mean of its divisors is an integer number (33346314415804).
Almost surely, 2116712100455307 is an apocalyptic number.
116712100455307 is a deficient number, since it is larger than the sum of its proper divisors (16673157207909).
116712100455307 is an equidigital number, since it uses as much as digits as its factorization.
116712100455307 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16673157207908.
The product of its (nonzero) digits is 176400, while the sum is 43.
The spelling of 116712100455307 in words is "one hundred sixteen trillion, seven hundred twelve billion, one hundred million, four hundred fifty-five thousand, three hundred seven".
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