Base | Representation |
---|---|
bin | 1010101001000101001010… |
… | …0101100001011001010011 |
3 | 1112102121000012101222111111 |
4 | 2222101102211201121103 |
5 | 3013201343334412011 |
6 | 40515150342554151 |
7 | 2315234425035334 |
oct | 252212245413123 |
9 | 45377005358444 |
10 | 11700876482131 |
11 | 380134a807601 |
12 | 138b85ba38957 |
13 | 66b507341c75 |
14 | 2c647b03428b |
15 | 154577695121 |
hex | aa452961653 |
11700876482131 has 4 divisors (see below), whose sum is σ = 11700915124600. Its totient is φ = 11700837839664.
The previous prime is 11700876482129. The next prime is 11700876482149. The reversal of 11700876482131 is 13128467800711.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11700876482131 - 21 = 11700876482129 is a prime.
It is a super-2 number, since 2×117008764821312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11700876782131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18863421 + ... + 19473838.
It is an arithmetic number, because the mean of its divisors is an integer number (2925228781150).
Almost surely, 211700876482131 is an apocalyptic number.
11700876482131 is a deficient number, since it is larger than the sum of its proper divisors (38642469).
11700876482131 is an equidigital number, since it uses as much as digits as its factorization.
11700876482131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38642468.
The product of its (nonzero) digits is 451584, while the sum is 49.
The spelling of 11700876482131 in words is "eleven trillion, seven hundred billion, eight hundred seventy-six million, four hundred eighty-two thousand, one hundred thirty-one".
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