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11705715551707 = 55072125606601
BaseRepresentation
bin1010101001010111001100…
…0001000110110111011011
31112110001111102222012000121
42222111303001012313123
53013241301140123312
640521310445014111
72315465354330032
oct252256301066733
945401442865017
1011705715551707
113803403297161
121390790554337
1366bac8a45748
142c67b99a3719
1515475c40d707
hexaa573046ddb

11705715551707 has 4 divisors (see below), whose sum is σ = 11707841163816. Its totient is φ = 11703589939600.

The previous prime is 11705715551693. The next prime is 11705715551773. The reversal of 11705715551707 is 70715551750711.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11705715551707 - 223 = 11705707163099 is a prime.

It is a super-2 number, since 2×117057155517072 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11705715551797) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1062797794 + ... + 1062808807.

It is an arithmetic number, because the mean of its divisors is an integer number (2926960290954).

Almost surely, 211705715551707 is an apocalyptic number.

11705715551707 is a deficient number, since it is larger than the sum of its proper divisors (2125612109).

11705715551707 is an equidigital number, since it uses as much as digits as its factorization.

11705715551707 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2125612108.

The product of its (nonzero) digits is 1500625, while the sum is 52.

The spelling of 11705715551707 in words is "eleven trillion, seven hundred five billion, seven hundred fifteen million, five hundred fifty-one thousand, seven hundred seven".

Divisors: 1 5507 2125606601 11705715551707