Base | Representation |
---|---|
bin | 1010101001110010111001… |
… | …1111000010110110100001 |
3 | 1112110202200221221012100211 |
4 | 2222130232133002312201 |
5 | 3013402020330100043 |
6 | 40524541025214121 |
7 | 2316150626521540 |
oct | 252345637026641 |
9 | 45422627835324 |
10 | 11713155706273 |
11 | 380658104242a |
12 | 1392108191341 |
13 | 66c7132abc78 |
14 | 2c6cc3b78157 |
15 | 154a456bda9d |
hex | aa72e7c2da1 |
11713155706273 has 8 divisors (see below), whose sum is σ = 13399890416192. Its totient is φ = 10029777684336.
The previous prime is 11713155706271. The next prime is 11713155706297. The reversal of 11713155706273 is 37260755131711.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11713155706273 - 21 = 11713155706271 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11713155706271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 839164515 + ... + 839178472.
It is an arithmetic number, because the mean of its divisors is an integer number (1674986302024).
Almost surely, 211713155706273 is an apocalyptic number.
It is an amenable number.
11713155706273 is a deficient number, since it is larger than the sum of its proper divisors (1686734709919).
11713155706273 is an equidigital number, since it uses as much as digits as its factorization.
11713155706273 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1678343991.
The product of its (nonzero) digits is 926100, while the sum is 49.
The spelling of 11713155706273 in words is "eleven trillion, seven hundred thirteen billion, one hundred fifty-five million, seven hundred six thousand, two hundred seventy-three".
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