Search a number
-
+
117134346283 = 519722538839
BaseRepresentation
bin110110100010111000…
…0000100100000101011
3102012100021221022121121
41231011300010200223
53404342343040113
6125451043320111
711314461341563
oct1550560044053
9365307838547
10117134346283
1145749315069
121a850080037
13b0795b0996
145952911da3
1530a85ece8d
hex1b45c0482b

117134346283 has 4 divisors (see below), whose sum is σ = 117156890320. Its totient is φ = 117111802248.

The previous prime is 117134346221. The next prime is 117134346311. The reversal of 117134346283 is 382643431711.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 382643431711 = 463826443697.

It is a cyclic number.

It is not a de Polignac number, because 117134346283 - 233 = 108544411691 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (117134346383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11264223 + ... + 11274616.

It is an arithmetic number, because the mean of its divisors is an integer number (29289222580).

Almost surely, 2117134346283 is an apocalyptic number.

117134346283 is a deficient number, since it is larger than the sum of its proper divisors (22544037).

117134346283 is an equidigital number, since it uses as much as digits as its factorization.

117134346283 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22544036.

The product of its digits is 290304, while the sum is 43.

Adding to 117134346283 its reverse (382643431711), we get a palindrome (499777777994).

The spelling of 117134346283 in words is "one hundred seventeen billion, one hundred thirty-four million, three hundred forty-six thousand, two hundred eighty-three".

Divisors: 1 5197 22538839 117134346283