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11714201857 = 43272423299
BaseRepresentation
bin10101110100011100…
…01000100100000001
31010020101100010000001
422322032020210001
5142442313424412
65214220000001
7563201034001
oct127216104401
933211303001
1011714201857
114a713a8266
12232b090001
131148b99cb7
147d1aa4001
15488619957
hex2ba388901

11714201857 has 4 divisors (see below), whose sum is σ = 11986625200. Its totient is φ = 11441778516.

The previous prime is 11714201801. The next prime is 11714201869. The reversal of 11714201857 is 75810241711.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11714201857 - 231 = 9566718209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11714201657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 136211607 + ... + 136211692.

It is an arithmetic number, because the mean of its divisors is an integer number (2996656300).

Almost surely, 211714201857 is an apocalyptic number.

It is an amenable number.

11714201857 is a deficient number, since it is larger than the sum of its proper divisors (272423343).

11714201857 is an equidigital number, since it uses as much as digits as its factorization.

11714201857 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 272423342.

The product of its (nonzero) digits is 15680, while the sum is 37.

The spelling of 11714201857 in words is "eleven billion, seven hundred fourteen million, two hundred one thousand, eight hundred fifty-seven".

Divisors: 1 43 272423299 11714201857