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117173004115 = 523434600823
BaseRepresentation
bin110110100100000001…
…1100010011101010011
3102012102222200100012011
41231020003202131103
53404432242112430
6125454544043351
711315441046616
oct1551003423523
9365388610164
10117173004115
1145769119292
121a861003557
13b0845c763b
145957ad617d
1530abbd722a
hex1b480e2753

117173004115 has 4 divisors (see below), whose sum is σ = 140607604944. Its totient is φ = 93738403288.

The previous prime is 117173004107. The next prime is 117173004217. The reversal of 117173004115 is 511400371711.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511400371711 = 618383612651.

It is a cyclic number.

It is not a de Polignac number, because 117173004115 - 23 = 117173004107 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11717300407 + ... + 11717300416.

It is an arithmetic number, because the mean of its divisors is an integer number (35151901236).

Almost surely, 2117173004115 is an apocalyptic number.

117173004115 is a deficient number, since it is larger than the sum of its proper divisors (23434600829).

117173004115 is an equidigital number, since it uses as much as digits as its factorization.

117173004115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23434600828.

The product of its (nonzero) digits is 2940, while the sum is 31.

Adding to 117173004115 its reverse (511400371711), we get a palindrome (628573375826).

The spelling of 117173004115 in words is "one hundred seventeen billion, one hundred seventy-three million, four thousand, one hundred fifteen".

Divisors: 1 5 23434600823 117173004115